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Together, two boys had 43 cents. The first boy spent 5 cents and the second boy spent 13 cents. The...
5 months ago
Q:
Together, two boys had 43 cents. The first boy spent 5 cents and the second boy spent 13 cents. The first boy’s remaining money is 2/3of the second boy’s remaining money. How much did they each have originally?
Accepted Solution
A:
hello kiddio lets figure this out!
Let x = first
y = second
Then
x - 5 = remainder of first
y - 13 = remainder of second
x - 5 = 2/3(y - 13)
3x - 15 = 2y - 26
3x - 2y = - 11................(1)
x + y = 43....................(2)
From (2) y = 43 - x..........(3)
Put (3) in (1)
3x - 2(43 - x) = - 11
3x - 86 + 2x = - 11
5x = 75
x = 15 cents
y = 43 - 15
= 28 cents
Have a nice day