4 months ago

Factor by grouping [tex]4r {}^{3} + 10r {}^{2} - 10r - 25[/tex]A.[tex](2r {}^{2} + 5)(2r - 5)[/tex]B.[tex](2r {}^+ 5)(2r {}^{2} - 5)[/tex]C.[tex](2r + 5)(2r {}^{2} - 5)[/tex]D.[tex](2r - 5)(2r {}^{2} - 5)[/tex]

Accepted Solution

Answer:CStep-by-step explanation:Nice work using latex. I admire anyone who has skills with it.It looks like this question can be grouped using to sets of brackets.(4r^3 + 10r^2) : Pull out the common factor. 2r^2* (2r + 5)The second set of brackets is a little bit tricker. Minus signs are not to be ignored. (-10r - 25) : -5(2r + 5)Now put both together,2r^2(2r + 5) - 5(2r + 5) Notice that there is a common factor on either side of that isolated minus sign. The common factor is 2r + 5. Use the distributive property to pull it out.(2r + 5)(2r^2 - 5)It looks like C will be the answer.

youyuan365

youyuan365

Factor by grouping [tex]4r {}^{3} + 10r {}^{2} - 10r - 25[/tex]A.[tex](2r {}^{2} + 5)(2r - 5)[/tex]B.[tex](2r {}^+ 5)(2r {}^{2} - 5)[/tex]C.[tex](2r + 5)(2r {}^{2} - 5)[/tex]D.[tex](2r - 5)(2r {}^{2} - 5)[/tex]

youyuan365

youyuan365

Factor by grouping [tex]4r {}^{3} + 10r {}^{2} - 10r - 25[/tex]A.[tex](2r {}^{2} + 5)(2r - 5)[/tex]B.[tex](2r {}^+ 5)(2r {}^{2} - 5)[/tex]C.[tex](2r + 5)(2r {}^{2} - 5)[/tex]D.[tex](2r - 5)(2r {}^{2} - 5)[/tex]​

Factor by grouping [tex]4r {}^{3} + 10r {}^{2} - 10r - 25[/tex]A.[tex](2r {}^{2} + 5)(2r - 5)[/tex]B.[tex](2r {}^+ 5)(2r {}^{2} - 5)[/tex]C.[tex](2r + 5)(2r {}^{2} - 5)[/tex]D.[tex](2r - 5)(2r {}^{2} - 5)[/tex]